The curve ax squared - 4x+1 has a stationary point where x equals -3 find the value of a and determine the nature of the stationary point

asked Oct 25, 2016 208k views

5 votes

The curve ax squared - 4x+1 has a stationary point where x equals -3

find the value of a and determine the nature of the stationary point

by Weber

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1 vote

$f(x)=ax^2-4x+1\\ f'(x)=2ax-4\\ 0=2a\cdot(-3)-4\\ 6a=-4\\ a=-(4)/(6)=-(2)/(3)$

It's the quadratic equation where
a<0

so the stationary point is a maximum.

Yedidya Reiss answered Oct 29, 2016

9.2k points

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