Question

WRITE AN EQUATION IN SLOPE INTERCEPT FORM OF THE LINE THAT PASSES THROUGH THE GIVEN POINT AND IS PARALLEL TO THE GRAPH OF THE GIVEN EQUATION (2,-2):Y=-X-2 I HAVE NO IDEA. I AM STRUGGLING SO BAD WITH THIS

Answer 1

The equation of the line that passes through the point (2, -2) and is parallel to the graph of the given equation y = -x - 2 is indeed y = -x + 0.

Here is an equation in slope-intercept form of the line that passes through the given point (2, -2) and is parallel to the graph of the given equation y = -x - 2:

Step 1: Determine the slope

The given equation y = -x - 2 is in slope-intercept form, which means it has the form y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is -1. Since parallel lines have the same slope, the slope of the line we are looking for is also -1.

Step 2: Substitute the point and slope into the slope-intercept form

The slope-intercept form of the equation is y = mx + b. We know that the slope is -1 and one of the points on the line is (2, -2). Substituting these values into the equation, we get:

-2 = -1(2) + b

Solving for b, we get:

b = 0

The equation in slope-intercept form is y = -x.

Answer 2

Okay, let's start with the given equation.
y=-x-2
The slope of that line would be -1
A line parallel to this would have the same slope of -1
Slope intercept form is y=mx+b
"m" is the slope and "b" is the y-intercept.
Substitute the given x and y values from the given point and the slope into this equation.
x=2, y=-2, m=-1 and we are solving for b
You then have:
-2=-1(2) + b
-2 = -2 + b
b= 0
Now, we have the y-intercept and the slope, which is all we need to create the equation
b=0, m=-1
Final answer: y=-x + 0 :)