3x + y = 12
2x + 3y = 1
Take the top equation and multiply it by -3
-9x - 3y = -36
2x + 3y = 1
Then, add the equations (Combine like terms
-7x = -35
Take both sides divided by -7
x = 5
The ordered pair is (5, 3) and x is infact 5, so continue
Then, plug in x for one of the other equations
3x + y = 12
3 (5) + y = 12
15 + y = 12
Subtract 15 from both sides
y = -3
Your ordered pair is (5, 3) but the y is not -3
No, the ordered pair is not a solution of the system of linear equations