Question

Find the zeros of the function by rewriting in intercept form.

Y=2X^2-4x

y=2C^2-11X-21

I need the answer and the work please.

Answer 1

The intercept form is
`y=a(x-p)(x-q)` where p, q - the zeroes of a function.

1.

`y=2x^2-4x \\ y=2x(x-2) \\ y=2(x-0)(x-2) \\ \hbox{the zeroes - }\boxed{x=0 \ and \ x=2}`

2.

`y=2x^2-11x-21 \\ y=2x^2-14x+3x-21 \\ y=2x(x-7)+3(x-7) \\ y=(2x+3)(x-7) \\ y=2(x+(3)/(2))(x-7) \\ y=2(x-(-(3)/(2)))(x-7) \\ \hbox{the zeroes - }\boxed{x=-(3)/(2) \ and \ x=7}`