Question

How do I solve: x/3 +10= 15

Answer 1

`(x)/(3)+10=15 \hbox10 (substract 10 from both)`


`(x)/(3)=15-10=5` ⇒
`x=3*5`


`\boxed {x=15}`

Answer 2

x/3+10=15
-10 -10
x/3= 5
x= 3*5
x=15

check by substitution 15/3 +10= 15
5+10=15, this is true
Therefore x=15 is the answer