Question

Solve each system using substitution.
3x+2y=23
1/2x-4=y

Answer 1

1: 3x+2y=23
2: 1/2x-4=y
We have that y=1/2x-4 in 2
So lets substitu y in 1
3x+2(1/2x-4)=23
3x+x-8=23
4x=23+8
4x=31
X = 7,75
Now lets replace x in 2:
1/2.7,75-4=y
3,875-4 + y
Y= - 0,125
So (x;y)=(7,75;-0.125)

Answer 2

`\left\{\begin{array}{ccc}3x+2y=23&(1)\\y=(1)/(2)x-4&(2)\end{array}\right\\\\subtitute\ (2)\ to\ (1)\\\\3x+2((1)/(2)x-4)=23\\3x+x-8=23\\4x-8=23\ \ \ \ |add\ 8\ to\ both\ sides\\4x=31\ \ \ \ \ |divide\ both\ sides\ by\ 4\\\boxed{x=7.75}\\\\subtitute\ the\ value\ of\`