Question

What are the solutions of 12-x2= 0?O x=2,3 and x = -2/3O x=3/5 and x = -3,2O x= 4/3 and x = -4/3O x = 6 and x = -6

Answer 1

The given equation is

`12-x^2=0`

Let's solve for x.

`\begin{gathered} 12=x^2 \\ x=\pm\sqrt[]{12} \\ x=\pm\sqrt[]{4\cdot3} \\ x=\pm2\sqrt[]{3} \end{gathered}`

Hence, the correct answer is the first answer choice.