I,m trying to solve this algebra question: x^+9x+20=0

asked Oct 3, 2016 22.4k views

2 votes

I,m trying to solve this algebra question:
x^+9x+20=0

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2 votes

Ok, let assume it's
x^2

$x^2+9x+20=0\\ x^2+4x+5x+20=0\\ x(x+4)+5(x+4)=0\\ (x+5)(x+4)=0\\ x=-5 \vee x=-4$

Thoean answered Oct 6, 2016

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${ x }^( 2 )+9x+20=0\\ \\ \left( x+5 \right) \left( x+4 \right) =0\\ \\ \therefore \quad x=-5,\quad x=-4.$

Giankotarola answered Oct 9, 2016

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