127k views
3 votes
Solve by completing the square

x squared +14x - 51=0

1 Answer

4 votes

x^2 +14x - 51=0\\ \\\Delta = b^(2)-4ac =14^(2)-4*1*(-51)=196+204=400 \\ \\x_(1)=(-b-√(\Delta ))/(2a) =(-14- √(400))/(2)=(-14-20)/(2)= (-34)/(2)=-17\\ \\x_(2)=(-b+√(\Delta ))/(2a) =(-14+ √(400))/(2)=(-14+20)/(2)= (6)/(2)=3


User Goddogsrunning
by
8.4k points

No related questions found