1. 5 moles
2. 75.6 grams
3. 2 moles
4. 1.806 x 10²⁴ particles
Further explanation
Given
mass and moles of compound
Required
mass, moles and number of particles
Solution
1. 530 g Na2CO3
mol = 530 g : 106 g/mol
mol = 5
2. 4.2 moles H2O
mass = 4.2 moles x 18 g/mol
mass = 75.6 grams
3. 12.04 x 10²³ O2
mol = 12.04 x 10²³ : 6.02 x 10²³
mol = 2
4. 3 moles of Mg
particles = 3 x 6.02 x 10²³
particles = 1.806 x 10²⁴