Question

Three and one third minus two and two fifths

Answer 1

`3(1)/(3)-2(2)/(5)\\\\find\ LCD((1)/(3);\ (2)/(5))\\\\3\ and\ 5\ are\ the\ prime\ numbers,\ therefore\ LCD=3\cdot5=15\\\\(1)/(3)=(1\cdot5)/(3\cdot5)=(5)/(15);\ (2)/(5)=(2\cdot3)/(5\cdot3)=(6)/(15)\\\\3(1)/(3)-2(2)/(5)=3(5)/(15)-2(6)/(15)=2(15+5)/(15)-2(6)/(15)=2(20)/(15)-2(6)/(15)=\boxed{(14)/(15)}`