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(45 POINTS!!!) Which is the equation of a parabola with a directrix at y = −3 and a focus at (−2, 3). y = one twelfth(x − 2) 2 y = one twelfth(x + 2) 2 y = −one twelfth(x + 2) 2 y = −one twelfth(x − 2)2
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(45 POINTS!!!) Which is the equation of a parabola with a directrix at y = −3 and a focus at (−2, 3).

y = one twelfth(x − 2)

2 y = one twelfth(x + 2)

2 y = −one twelfth(x + 2)

2 y = −one twelfth(x − 2)2

User Elson Ramos
by
3.3k points

2 Answers

8 votes

Answer:

y = −one twelfth(x − 2)2

Explanation:

User Juanito Fatas
by
3.8k points
10 votes

Answer:

y = −one twelfth(x − 2)2

Explanation:

y = −one twelfth(x − 2)2

User ACVM
by
3.5k points
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