Question

Find the distance, to the nearest tenth, from T(4,-2) to U(-2,3).

Answer 1

`d = \sqrt{ (x_(1) - x_(2))^(2) + (y_(1) - y_(2))^(2) } \\ d = \sqrt{ (4 - (-2))^(2) + (-2 - 3)^(2) } \\ d = \sqrt{ (6)^(2) + (-5)^(2) } \\ d = √( 36 + 25) \\ d = √( 61 ) \\ d = 7.81024... \\ d = 7.8`

Answer 2

7.81

Explanation:

Using the formula for finding the distance between two points as shown:

TU = √(y2-y1)²+(x2-x1)²

Given T = (4,-2) and U = (-2,3)

x1 =4, y1 = -2, x2 = -2, y2 = 3

Substituting this values into the formula, we have;

TU = √{3-(-2)}²+(-2-4)²

TU = √(3+2)²+(-2-4)²

TU = √5²+(-6)²

TU = √25+36

TU = √61

TU = 7.81

The distance between the two points is 7.81