S is the sum of the first 100 consecutive positive even integers, and T' is the sum of the first 100 consecutive positive integers. S is what percent greater than T?
A. 100%
B. 50%
C.10%
D.2%
we have that
t=1/2 * n(n+1) = sum all numbers from 1 to n
For n=100
t=1/2 * 100(100+1)=5,050
s=n(n+1) = sum 1st n even numbers
s=100(100+1)=10,100
so
s/t=10,100/5,050
s/t=2
therefore
the answer is 100%
option A