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Solve for x 27^(2x+4)=1/9^(x-46)

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27^(2x+4)=((1)/(9))^(x-46) \\ (3^3)^(2x+4)=(3^(-2))^(x-46) \\ 3^(3(2x+4))=3^(-2(x-46)) \\ 3^(6x+12)=3^(-2x+92) \\ 6x+12=-2x+92 \\ 6x+2x=92-12 \\ 8x=80 \\ x=10
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