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Write an equation in point-slope form of the line through the given points. Then write the equation in slope-intercept form.

(-10,-6);m = -5/8

User Badp
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y-y_1=m(x-x_1) \\ \\ m=-(5)/(8) \\ (-10,-6) \\ x_1=-10 \\ y_1=-6 \\ \Downarrow \\ y-(-6)=-(5)/(8)(x-(-10)) \\ \boxed{y+6=-(5)/(8)(x+10)} \ - \ \hbox{the point-slope form} \\ \\ y+6=-(5)/(8)(x+10) \\ y+6=-(5)/(8)x-(50)/(8) \\ y=-(5)/(8)x-(50)/(8)-6 \\ y=-(5)/(8)x-(25)/(4)-(24)/(4) \\ y=-(5)/(8)x-(49)/(4) \\ \boxed{y=-(5)/(8)x-12 (1)/(4)} \ - \ \hbox{the slope-intercept form}
User DirkyJerky
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