Question

ALGEBRA HELP, please help with problem, and show work

Answer 1

divide both sides by 4x:
x^2-2x+1=0
You can either factor, complete the square, or use the quadratic formula.
I'll factor this into (x-1)(x-1)=0
x-1=0, so x=1

Answer 2

First of all, your second term is already wrong. When you divided 8x² by 4 ,
you should have written 2x² , not 4x² .

Make that correction, and then divide the whole thing by 'x'.

Then you'll have x² - 2x + 1 = 0 .

You should have no trouble solving that one,
(especially since it's a perfect square)

That gives you two (equal) solutions. But you should also ask yourself:
"Self ! Where is the third solution ? A cubic equation like the original
one needs three solutions."

I'll give you that one:
Look over the original equation, and look at what happens to it when x = 0 .
Then the left side becomes zero, and the equation is 0 = 0 . Since that's a
true statement, " x = 0 " is another solution of the cubic equation, and now
you have all three of them.