Question

I need help with this function

Answer 1

`f(x)=3x^2+1\\ g(x)=2x+2\\\\ y=2x+2\\ 2x=y-2\\ x=(1)/(2)y-1\\ g^(-1)(x)=(1)/(2)x-1\\\\ (f\cdot g)(x)=f(x)\cdot g(x)\\\\ (f\cdot g^(-1))(2)=(3\cdot2^2+1)(2\cdot2+2)\\ (f\cdot g^(-1))(2)=(12+1)\cdot6\\ (f\cdot g^(-1))(2)=13\cdot6\\ (f\cdot g^(-1))(2)=78`