Question

If 4.5 moles of AlCl3 were made, how many moles of CuCl2 were used?

Answer 1

6.75 moles of CuCl₂ were used

Step-by-step explanation:

Given data:

Number of moles of AlCl₃ formed = 4.5 mol

Number of moles of CuCl₂ used = ?

Solution:

Chemical equation:

3CuCl₂ + 2Al → 2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ and AlCl₃

AlCl₃ : CuCl₂

2 : 3

4.5 : 3/2×4.5 = 6.75

6.75 moles of CuCl₂ were used.