Find all values of x satisfying the given conditionsY1 = 2(4x - 7) - 8, Y2 = 5(x-3) + 14, Y1 = Y2

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17 votes

we have the equations

$\begin{gathered} y_1=2(4x-7)-8 \\ y_2=5(x-3)+14 \end{gathered}$

Equate y1 and y2

$\begin{gathered} 2(4x-7)-8=5(x-3)+14 \\ solve\text{ for x} \\ 8x-14-8=5x-15+14 \\ 8x-22=5x-1 \\ 8x-5x=-1+22 \\ 3x=21 \\ x=7 \end{gathered}$

Matko answered Apr 9, 2023

by Matko

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