Question

What are the possible values of x in 32x + 20 = 28x − 16x2?

Answer 1

2x+20=−16x2+28xStep 2: Subtract -16x^2+28x from both sides.2x+20−(−16x2+28x)=−16x2+28x−(−16x2+28x)16x2−26x+20=0Step 3: Use quadratic formula with a=16, b=-26, c=20.x=−b±√b2−4ac2ax=−(−26)±√(−26)2−4(16)(20)2(16)x=26±√−60432

Answer 2

4x2+x+5=0
(2x+1/4)^2=-79/16
2x+1/4=(√79/4) i or 2x+1/4=-(√79/4) i
x=(√79/8) i -1/8 or -(√79/8) i -1/8