Given a slope of 2/3 and a y-intercept of -6, write the equation of the line in slope intercept form y=(2/3)x-6 y=-6x+(2/3) y=3x+2 6=2x+3

asked Apr 25, 2017 10.9k views

4 votes

Given a slope of 2/3 and a y-intercept of -6, write the equation of the line in slope intercept form

y=(2/3)x-6

y=-6x+(2/3)

y=3x+2

6=2x+3

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3 votes

Y = slope× X + y intercept
so the answer will be
y = (2/3)X -6

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