Final answer:
The thunderclap at 102 dB is approximately 80 times louder than the dog's bark at 83 dB. To determine this, a 10 dB increase corresponds to a 10 times higher intensity, and we approximate the 9 dB remaining after the first 10 dB increase.
Step-by-step explanation:
To determine how many times louder the thunderclap is than the dog's bark, we use the difference in decibels (dB) as a logarithmic measure of sound intensity. The given sound levels are 83 dB for the dog and 102 dB for the thunderclap. First, we calculate the difference in dB, which is:
102 dB - 83 dB = 19 dB
We know that a 10 dB increase represents a sound that is 10 times more intense. Therefore, for each 10 dB difference, we multiply the intensity by 10. In this case, we have a 19 dB difference. This can be split into one full 10 dB difference and a 9 dB difference. From the provided information, we can deduce that a 7 dB increase corresponds to a 5 times intensity increase. Thus, a 9 dB difference would indicate a slightly higher intensity factor.
Therefore, the thunderclap is approximately 10 * 8 = 80 times louder than the dog's bark.