Question

A 60-kg skate boarder is standing on his stationary board. A bigger, out of control 75-kg skate boarder crashes into him with a velocity of 4 m/s. Their boards get stuck together in this inelastic collision. How fast are the moving after the collision?

Answer 1

2.22m/s

Step-by-step explanation:

Given parameters:

M1 = 60kg

M2 = 75kg

V1 = 0m/s

V2 = 4m/s

Unknown;

Velocity after collision = ?

Solution:

To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;

M1 V1 + M2 V2 = v(M1 + M2)

So;

60 x 0 + 75 x 4 = v (60 +75)

300 = 135v

v = 2.22m/s