Question

The temperature of 100. grams of water changes from 16.0ºC to 20.0ºC. What is the total number of Joules of heat energy absorbed by the water?

Answer 1

To find the heat energy absorbed by the water as its temperature increases from 16.0°C to 20.0°C, we use the specific heat capacity formula with a specific heat of 4.184 J/g°C, resulting in 1673.6 Joules of heat absorbed.

Step-by-step explanation:

To calculate the total number of Joules of heat energy absorbed by the water, we use the specific heat capacity formula: q = mcΔT, where q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. The specific heat capacity of water (c) is 4.184 J/g°C. In this case, the mass (m) of the water is 100 grams, and the temperature change (ΔT) is from 16.0°C to 20.0°C, which is a change of 4.0°C.

Using the formula:

q = (100 g) × (4.184 J/g°C) × (4.0°C)

q = 1673.6 J

So, the water absorbs 1673.6 Joules of heat energy

Answer 2

1. Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 100(4.184)(20 - 16)
Heat = 1673.6 J