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Under what pressure will a scientist need to store 0.400 moles of gas if the container has a volume of 200.0 mL and the temperature is kept at 23.0 C?

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Answer: 48.60 atm

Explanation: Using ideal gas equation:


PV=nRT


P=(nRT)/(V)

P= pressure = ? atm

V= volume =
200ml=0.2L

n = no of moles = 0.400

R= gas constant =0.0821 Latm/molK

T = Temperature
=23^0C=(23+273)K=296K


P=(0.400* 0.0821* 296K)/(0.2L)=48.60atm

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