188k views
5 votes
Does the equation sin2(x) – 4 = 0 have any solutions? Explain.

User HaleFx
by
8.6k points

2 Answers

0 votes

Answer:

No, the given equation:


\sin^2x-4=0

does not have any solution.

Explanation:


sin^2x-4=0\\\\this\ means\ that\\\\(sinx-2)(sinx+2)=0\\\\so\ either\ sinx-2=0 or\ sinx+2=0\\\\i.e. sinx=2 or\ sinx=-2\\\\but\ this\ is\ not\ true\ as\ value\ of\ sinx\ lies\ between\ -1\ and\ 1

Hence, the given equation:


\sin^2x-4=0 does not have any solution.

User Richard Grimshaw
by
8.2k points
5 votes
Isolate sin(x) by adding 4 and taking the square root of both sides.
State that sin(x) = 2 or sin(x) = –2.State that –2 and 2 are undefined values of the inverse sine function.There are no solutions because –2 and 2 are not in the domain of the function.
User Doodeec
by
7.7k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories