Question

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the student use to make the sample? Use mc020-1.jpg. 3.70 mL 16.7 mL 30.0 mL 83.3 mL

Answer 1

A) 3.70 mL B) 16.7 mL C) 30.0 mL D) 83.3 mL

It is C 30.0 mL

Answer 2

Answer is 30.0mL

according to the question dilution is performed by the student which can be calculated with the help of :

`M_(1)V_(1)=M_(2)V_(2)` EQUATION (1)

Here, we have:

`M_(1)` = 3M

`V_(1)` = y mL

`M_(2)`= 1.80 M

`V_(2)` = 50.0mL

putting the known values in equation (1) which will give us value of
`V_(1)`

3.00× y =1.80 ×50.0

y= 30.0mL