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An object's motion is described by the equation d = 4 sin(pi t ) . The displacement, d , is measured in meters. The time, t , is measured in seconds. Answer the following questions:

(a) What is the object's position at t = 0 ?
(b) What is the object's maximum displacement from its resting position?
(c) How much time is required for one oscillation?
(d) What is the frequency?

User Mcmlxxxvi
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2 Answers

3 votes

Answer:

Explanation:

The given equation is:


d=4sin({\pi}t), where d is the displacement. (1)

(A) The position of the object at t=0 is:


d=4sin({\pi}(0))


d=4sin(0)


d=0

The object will be at rest at t=0.

(B) In order to find the maximum displacement from the resting position, we will differentiate the given displacement.

Thus, Differentiating with respect to t, we have


d'=4cos({\pi}t)({\pi})


d'=4{\pi}cos({\pi}t)

Now, d'=0


4{\pi}cos({\pi}t)=0


cos{\pi}t=0


{\pi}t=\frac{{\pi}}{2}


t=(1)/(2)

Substitute the value of t in equation (1), we get


d=4sin({\pi}((1)/(2)))


d=4(1)


d=4m

Thus, the maximum displacement from its resting position will be 4m.

(C) Time required for one oscillation is equal to the period which is equal to=
(2\pi)/(|b|)=(2\pi)/(\pi)=2

thus, time required for one oscillation will be 2 seconds.

(D) Frequency is nothing but the reciprocal of period that is
(|b|)/(2\pi)=(\pi)/(2\pi)=(1)/(2)

Thus, the frequency will be equal to
(1)/(2).

User Punkouter
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6.8k points
4 votes
The equation of the motion is
d = 4 sin (π t)

a) When t = 0
d = 4 sin 0
d = 0

b) We take the derivative
4π cos πt = 0
t = 1/2
d = 4 sin π/2 = 4 meters

c) 1 second is required

d) The frequency is 1Hz
User Maguy
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8.1k points