Question

You have 500 grams of CaCO3. How many moles are present? a 8 b 5 c 2 d 10

Answer 1

b. 5

Step-by-step explanation

The moles of CaCO3 present in 500 grams of CCO3 can be calculated using the mole formula.

`Mole=\frac{Mass}{Molar\text{ }mass}`

Molar mass of CaCO3 100 g/mol

Putting mass = 500 g and molar mass = 100 g/mol into the mole formula, we have,

`Mole=\frac{500\text{ }g}{100\text{ }g\text{/}mol}=5\text{ }moles`

The moles of CaCO3 resent in 500 grams of CacCO3 = 5 moles