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16 votes
16 votes
Does a maximum value exist for y = 8x^2 + 80x + 72? Explain your answer.

User Ashok Kumar
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1 Answer

13 votes
13 votes

Solution

Reason 1:


\begin{gathered} y=8x^2+80x+72 \\ \\ \Rightarrow(dy)/(dx)=16x+80 \\ \\ (d^2y)/(dx^2)=16>0(\text{ Minimum\rparen} \end{gathered}

Reason 2:

Since the coefficient of x is positive, the graph is going to be minimum.

Maximum value does not exist.

User Spongessuck
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2.7k points