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For the function f(x) = (8-2x)2 ,find f-1 . Determine whether f-1 is a function.

A.
f-1(x) = ;f-1 is a function


B.
f -1 (x) = ; f-1 is not a function


C.
f-1(x) = ;f-1 is not a function


D.
f-1(x) = ; f-1 is a function

2 Answers

6 votes
f(x) = (8-2x)2=y
let 's find the inverse is
(8-2x)2=y, (8-2x)=sqrt(y), and -2x=sqrt(y) -8, finally x= (-1/2)sqrt(y)+4
the inverse is f^-1(y)=(-1/2)
√y + 4, when x=y

the inverse is f^-1(x)=(-1/2) √x + 4

A: f-1(x) = ;f-1 is a function
User Chkdsk
by
8.2k points
4 votes

Answer:


y=(8\pm√(x))/(2)

Step-by-step explanation:

We have been given with a function
f(x)=(8-2x)^2

We need to find
f^(-1)

when we find inverse of any function we intechange the variables we will get


x=(8-2y)^2 after simplification we will get


y=(8\pm√(x))/(2)


f^(-1) is not a function since, for each value of x there is two values of y.

User Sergey Alekseev
by
8.6k points

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