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What is the average velocity of atoms in 1.50 mol of neon (a monatomic gas) at 278 K? For m, use 0.01500 kg. Remember that R = 8.31 J/(molK).

A. 9610 m/s
B. 832 m/s
C. 6.93 m/s
D. 693,000 m/s

2 Answers

2 votes

Answer: 832m/s

Step-by-step explanation:

User Taylor Rahul
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3 votes

Answer:

B. 832 m/s

Step-by-step explanation:

(1/2) (0.015) v^2 = (3/2) (1.5) (8.31) (278)

0.0075 v^2 = 5197.905

v^2 = 693054

v = 832.49

User Stan Bright
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8.0k points