Question

Write the equation of line that has a slope 3/5 and passes through the point (-10,-16)

Answer 1

It is required to find the equation of the line with a slope 3/5 and passes through (-10,-16)

The general equation of the line is y = mx + b

Where m is the slope and b is a constant

Given : the slope = m = 3/5

So, the equation will be:

`y=(3)/(5)x+b`

Find the value of b using the given point ( -10 , -16 )

`\begin{gathered} -16=(3)/(5)\cdot-10+b \\ -16=-6+b \\ b=-16+6=-10 \end{gathered}`

So, the equation of the line is:

`y=(3)/(5)x-10`