Final answer:
On average, you would need to attempt 10 times in order to win once, given a 1 in 10 chance of winning, according to the principles of a geometric distribution in probability.
Step-by-step explanation:
This is a classic example of a geometric distribution problem in probability where each trial is independent, and the probability of success (in this case, winning) remains constant with each trial. To find the expected number of trials until the first success, you can use the formula: expected number of trials = 1/p, where p is the probability of winning on any single trial. Since the probability of winning is 1/10, the expected number of trials is 1/(1/10) = 10 trials. Therefore, on average, you would need to try 10 times in order to win once.