Question

Engineers want to design brakes that will reduce stopping distances by 10%. How would this change the equation relating speed s, friction f, and stopping distance d?

s=√30fd

Answer 1

For the answer to the question above, we will use this formula to solve this problem
d = kv^2

plugging in,
4.2 = k*10^2
k = 0.042

d = 0.042v^2

the revoised equation will be
d = 0.9*0.042v^2 , i.e.

d = 0.0378v^2

I hope my answer helped you