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The point (8, –15) is on the terminal side of an angle θ. What is sin θ ?

2 Answers

7 votes

Answer:


\sin \theta = -(15)/(17)

Explanation:

Given the point (8, -15) is on the terminal side of an angle
\theta.

To find the value of
\sin \theta.

As the point (8, -15) lies in the fourth quadrant where
\sin \theta < 0

In a right angle triangle;

here, adjacent side = x = 8 units and Opposite side = y = -15 units

Using Pythagoras theorem;


(Hypotenuse side)^2 = (Adjacent side)^2+(Opposite side)^2

Substitute the given values we have;


(Hypotenuse side)^2 = (8)^2+(-15)^2


(Hypotenuse side)^2 = 64+ 225 = 289


Hypotenuse side = √(289) =17 units

Sine ratio is defined as in the right angle triangle, the ratio of opposite side to Hypotenuse side.


\sin \theta = (Opposite side)/(Hypotenuse side)

then;


\sin \theta = -(15)/(17)

therefore, the value of
\sin \theta is
-(15)/(17).


The point (8, –15) is on the terminal side of an angle θ. What is sin θ ?-example-1
User Darkstarone
by
8.2k points
4 votes
For the answer to the question What is sin θ ? (8, -15) is in quadrant IV.

Draw the right triangle.
hypotenuse = √(8² + 15²) = 17
sinθ = -15/17

Just draw the graph for reference.

I hope my answer helped you. Feel free to ask more questions. Have a nice day!
User Juliushuck
by
8.4k points

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