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A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).

User Clonejo
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Hello there.
A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).m = (y2 - y1) / (x2 - x1)
User Aronisstav
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For the answer to the question above,
The slope of the line of the line is calculated through the equation,
m = (y2 - y1) / (x2 - x1)

Using the first two points in the given,
m = (-7 - 9) / (-12 - 8) = 4/5

The line parallel to this has also a slope of 4/5. Through the point-slope form, the equation of the second line is,
y - -15 = (4/5)(x - -5)

Simplifying gives the answer of,
y = (4/5)x -11

Eliminating the fraction,
5y = 4x - 55

I hope my answer helped you.
User Neil Agarwal
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