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Janis divided the two polynomials shown: 4x+2(4x^2-10x-6) A: x+3 B: x-3 C: x-2 + -2/4x+2 D: x-2+-10/4x+2
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Janis divided the two polynomials shown: 4x+2(4x^2-10x-6) A: x+3 B: x-3 C: x-2 + -2/4x+2 D: x-2+-10/4x+2
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Aug 28, 2017
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Janis divided the two polynomials shown:
4x+2(4x^2-10x-6)
A: x+3
B: x-3
C: x-2 + -2/4x+2
D: x-2+-10/4x+2
Mathematics
high-school
DrStalker
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Hello there.
Janis divided the two polynomials shown:
4x+2(4x^2-10x-6)
B: x-3
Graziela
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Aug 29, 2017
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Graziela
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For the answer to the question above, I'll provide a solution on how I got my answer below.
(4x+2)/(4x^2-10x-6)
= (4x+2)/[(4x+2)(x-3)]
= 1/(x-3)
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
RageD
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Sep 3, 2017
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RageD
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