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How do you transform the polar equation theta=pi/6 to an equation in rectangular coordinates and identify its shape?

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You are given the theta function θ=π/6, suppose that you have a radius of 4, then we have a polar coordinate of (4,π/6). To change into rectangular form, this is also equal to
x = 4cosπ/6 and y = 4sinπ/6
x = 2√3 and y = 2
(2√3, 2)
User Kendsnyder
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