Question

How many moles of KI are present in 0.250 L of a 2.30 M solution?

Answer 1

Remember that the formula of molarity is the following:

`\text{Molarity}=\frac{\text{moles of solute}}{liters\text{ of solution.}}`

We just have to solve for 'moles of solute' and replace the values that we have of molarity (2.30 M) and volume (0.250 L):

`\begin{gathered} \text{moles of solute = Molarity}\cdot liters\text{ of solution,} \\ \text{moles of solute = 2.30 M }\cdot\text{ 0.250 L,} \\ \text{moles of solute= 0.575 moles.} \end{gathered}`

The answer is that we have 0.575 moles of KI in a 0.250 L of a 2.30 M solution.