Question

Vitellium (Vi) has the following composition:

Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%
Based on this data, what can you predict about the average atomic mass of vitellium?

Answer 1

192.1055 to 4 decimal places. If you want the workings out, don't hesitate to ask.

Answer 2

The average atomic mass of vitellium is 192.11 amu.

Step-by-step explanation:

The average atomic mass is an average between the masses of all the isotopes, considering their abundance in the nature. It can be calculated using the following expression:

`AAM=(\Sigma m_(i) * ab_(i)  )/(100)`

where,

`m_(i)` is the mass of each isotope.

`ab_(i)` is the abundance in the nature of each isotope.

For vitelium,

`AAM=(187.9122amu * 10.861 + 190.9047amu * 12.428 + 192.8938 amu* 76.711 )/(100) =192.11amu`