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Point O is the center of the circle in the diagram. What is m∠BCA ? A80° B75° C70° D65°
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Point O is the center of the circle in the diagram. What is m∠BCA ?

A80°
B75°
C70°
D65°

User Zacho
by
8.3k points

1 Answer

4 votes
m ∠ BOA = 360° - 250° = 110°
The sum of all interior angles of the quadrilateral AOBC is 360°
m ∠ BCA = 360° - ( 110° + 90° + 90° ) = 360° - 290° = 70°
Answer: C ) 70°
User Mohammad Nikdouz
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9.4k points
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