7.3k views
3 votes
Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is 28 square meters.

The side of the retangle measure ? Meters

User Mgrouchy
by
8.2k points

2 Answers

7 votes
I hope this helps you
Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is-example-1
User Hemerson Carlin
by
8.6k points
4 votes

Answer:

The length is 7 meters.

The width is 4 meters.

Explanation:

The area of the rectangle is = 28 sq meter

The perimeter of the rectangle is = 28 sq meter

Now, in terms of formula these can be written as :


l* w=28

or
l=(28)/(w) ....(1)


2l+2w=22

Dividing by 2


l+w=11 .... (2)

Now, putting (1) in (2)


(28)/(w)+w=11


28+w^(2) =11w


w^(2)-11w+28=0


w^(2)-7w-4w+28=0


w(w-7)-4(w-7)=0


(w-4)(w-7)=0

This gives width as 4 , so length = 7

Or width as 7 , so length = 4

Therefore, the length is 7 meters.

The width is 4 meters.

User Dylan Anlezark
by
7.9k points