90.4k views
3 votes
1. Divide. Assume the denominator does not equal zero.

12x²y - 6xy + 4x²/2xy

2. Factor completely
2x²y + 12xy + 18y

User Vrtis
by
7.1k points

1 Answer

6 votes
Q1. The answer is
6x-3+ (x)/(y) + (2x)/(y)


(12 x^(2) y-6xy+4 x^(2) )/(2xy) = (12 x^(2)y)/(2xy) -(6xy)/(2xy) +(4x^(2))/(2xy) =6x-3+ (x)/(y) + (2x)/(y)

Q2. The answer is
2y(x+2)^(2)


2 x^(2) y + 12xy + 18y \\ =2( x^(2) y + 6xy + 9y) \\ =2y( x^(2) +6x+9) \\ =2y( x^(2) +2*x*3+ 3^(2) ) \\ =2y(x+2)^(2)
User Jenseb
by
8.0k points