PLEASE SOLVE \log \left(x\right)=log\left(2x^2\right)-2

asked May 10, 2023 117k views

2 votes

PLEASE SOLVE

$\log \left(x\right)=log\left(2x^2\right)-2$

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4 votes

Answer:

x = 50

Explanation:

$\log _(10)\left(x\right)=\log _(10)\left(2x^2\right)-2$

$\log _(10)\left(x\right)=\log _(10)\left(2x^2\right)-\log _(10)\left(100\right)$

$\log _(10)\left(x\right)=\log _(10)\left((2x^2)/(100) \right)$

x = (2x^2)/(100)

100x=2x^2

x^2 = 50x

x = 50

Lior Dahan answered May 15, 2023

4.8k points

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