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What is the ΔG for the following reaction at 25°C? SO3(g) + H2O(l) → H2SO4(l) Given: SO3(g):ΔG= –368 kJper mole H2O(l):ΔG= –237 kJ per mole H2SO4(l):ΔG= –689.9 kJ per mole 84.9 kJ 558.9 kJ –84.9 kJ –558.
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Feb 19, 2017
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What is the ΔG for the following reaction at 25°C?
SO3(g) + H2O(l) → H2SO4(l)
Given:
SO3(g):ΔG= –368 kJper mole
H2O(l):ΔG= –237 kJ per mole
H2SO4(l):ΔG= –689.9 kJ per mole
84.9 kJ
558.9 kJ
–84.9 kJ
–558.9 kJ
Chemistry
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RobertoAllende
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Answer: -84.9 kJ
Step-by-step explanation:
MaGnetas
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Feb 20, 2017
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MaGnetas
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We write the equation as:
-368 + -237 = ΔH + -689.9
ΔH = 84.9 kJ/mol
When written outside of the reaction equation, its sign will be reversed.
Thus, ΔH = -84.9 kJ/mol
The third option is correct.
Kagundajm
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Feb 25, 2017
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Kagundajm
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