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If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2 KClO3 → 2 KCl + 3 O2
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If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2 KClO3 → 2 KCl + 3 O2
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Sep 5, 2017
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If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?
2 KClO3 → 2 KCl + 3 O2
Chemistry
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Daniel Beltrami
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Moles of KClO₃ = 59.3 / (39 + 35.5 + 16 x 3)
Moles of KClO₃ = 0.48
Molar ratio of KClO₃ to O₂ = 2 : 3
Moles of O₂ produced = 1.5 x 0.48
= 0.72
Mass of O₂ = moles x Mr
= 0.72 x 32
= 23.04 grams
Milos Kovacevic
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Sep 11, 2017
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Milos Kovacevic
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