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If the speed of a ball increased from 1 m/s to 4 m/s, by how much would kinetic energy increase?

1 Answer

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We Know, K.E. = mv²/2
Here, v' = 4v
so, K.E' = mv'²/2
K.E' = m(4v)² / 2
K.E.' = 16 * mv²/2

It means, Kinetic energy will increase by 16 times.

Hope this helps!
User Daxnitro
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