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A circuit contains three resistors connected in series. the value of r1 is 150 , the value of r2 is 60 , and the value of r3 is 620 . what is the total resistance in the circuit?

User Xzibit
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2 Answers

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For calculating the total value of the resistances in a series circuit, we just add all of the values. In this case, it would be 150+60+620 which is 830Ω
User Jonny Vu
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Answer:

830 Ω

Step-by-step explanation:

For the resistors connected in series the voltage flowing through them is different while the current flowing through them is the same.

The reason for the different voltages flowing through each resistor in series is due to the resistance that each resistor preceding the other poses to the voltage that is passed through it. the formula used for calculating resistance of resistors in series is = R1 + R2 + R3 while for calculating resistance in parallel is = 1/R1 + 1/R2 + 1/R3 = 1/Ret

R1 + R2 + R3 = 150 + 60 + 620 = 830 Ω

User Simon Barkhuizen
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